The number of photons emitted in 10 hours by a 60 W sodium lamp (λ = 5893 mathringA) will be :

Question

The number of photons emitted in 10 hours by a 60 W sodium lamp (λ = 5893 mathringA) will be : (A) 1.6 × 1024 (B) 3.2 × 1024 (C) 6.4 × 1024 (D) 8 × 1023

Tardigrade Admin · Accepted Answer

Energy of 1 photon =( hc /λ) =(6.62 × 10-34 × 3 × 108/5893 × 10-10) =3.37 × 10-19 J Total energy emitted by sodium lamp =60 Watt =60 J / sec ∴ Number of photon emitted in 1 sec =(60/3.37 × 10-19) and in 10 hours Total no. of emitted photons =(10 × 3600 × 60/3.37 × 10-19) =6.4 × 1024

Q. The number of photons emitted in $10$ hours by a $60 W$ sodium lamp $(λ = 5893 \overset{˚}{A}$ ) will be :

$1.6 \times 1 0^{24}$

$3.2 \times 1 0^{24}$

$6.4 \times 1 0^{24}$

$8 \times 1 0^{23}$

Q. The number of photons emitted in 10 hours by a 60W sodium lamp (λ=5893A˚) will be :

1.6×1024

3.2×1024

6.4×1024

8×1023

Energy of 1 photon =λhc​ =5893×10−106.62×10−34×3×108​ =3.37×10−19J Total energy emitted by sodium lamp =60Watt=60J/sec ∴ Number of photon emitted in 1sec=3.37×10−1960​ and in 10 hours Total no. of emitted photons =3.37×10−1910×3600×60​ =6.4×1024

Q. The number of photons emitted in $10$ hours by a $60 W$ sodium lamp $(λ = 5893 \overset{˚}{A}$ ) will be :

$1.6 \times 1 0^{24}$

$3.2 \times 1 0^{24}$

$6.4 \times 1 0^{24}$

$8 \times 1 0^{23}$