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Tardigrade
Question
Chemistry
The number of orbitals with n = 5, m1 = + 2 is . (Round off to the Nearest Integer).
Q. The number of orbitals with
n
=
5
,
m
1
=
+
2
is ______. (Round off to the Nearest Integer).
2009
183
JEE Main
JEE Main 2021
Structure of Atom
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Answer:
3
Solution:
For,
n
=
5
ℓ
=
(
0
,
1
,
2
,
3
,
4
)
If
ℓ
=
0
,
m
=
0
ℓ
=
1
,
m
=
{
−
1
,
0
,
+
1
}
ℓ
=
2
,
m
=
{
−
2
,
−
1
,
0
,
+
1
,
+
2
}
ℓ
=
3
,
m
=
{
−
3
,
−
2
,
−
1
,
0
,
+
1
,
+
2
,
+
3
}
ℓ
=
4
,
m
=
{
−
4
,
−
3
,
−
2
,
−
1
,
0
,
+
1
,
+
2
,
+
3
,
+
4
}
5
d
,
5
f
and
5
g
subshell contain one-one orbital having
m
ℓ
=
+
2