The number of meso form of the given compound (.A.) is

Question

The number of meso form of the given compound (.A.) is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/c-qm7mppz6lixxbrau.jpg" /> (A) 2 (B) 3 (C) 4 (D) 8

Tardigrade Admin · Accepted Answer

Number of meso form 2(. ( textn - 1/2) .) when compound is divisible into two identical halves and has odd number of chiral carbons. textm = 2(. (3 - 1/2) .) =21=2 .

Q. The number of meso form of the given compound $(A)$ is

2

3

4

8

Number of meso form $2^{(\frac{n - 1}{2})}$ when compound is divisible into two identical halves and has odd number of chiral carbons.
$m = 2^{(\frac{3 - 1}{2})}$
$= 2^{1} = 2$ .

Q. The number of meso form of the given compound (A) is

2

3

4

8

Number of meso form 2(2n−1​) when compound is divisible into two identical halves and has odd number of chiral carbons. m=2(23−1​) =21=2 .

Q. The number of meso form of the given compound $(A)$ is

Number of meso form $2^{(\frac{n - 1}{2})}$ when compound is divisible into two identical halves and has odd number of chiral carbons.
$m = 2^{(\frac{3 - 1}{2})}$
$= 2^{1} = 2$ .