Question

The number of integral solution(s) of the equation $xyz=360$ is $180m$, then m equals

• A. 4
• B. 3
• C. 2
• D. 1

Answer 1

Answer: (A)

$xyz=360$
$xyz=2^3\times 3^2\times 5$
Number of natural solutions are ${}^5{C}_2\times {}^4{C}_2\times {}^3{C}_2=180$
Number of integral solutions are $=4\times 180$
$\Rightarrow m=4$.