Tardigrade
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Tardigrade
Question
Chemistry
The number of geometric isomers that can exist for square planar [ Pt ( Cl )( py )( NH 3). .( NH 2 OH )]+ is ( py = pyridine ):
Q. The number of geometric isomers that can exist for square planar
[
Pt
(
Cl
)
(
p
y
)
(
N
H
3
)
(
N
H
2
O
H
)
]
+
is
(
p
y
=
pyridine
)
:
2075
243
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JEE Main 2015
Coordination Compounds
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A
2
8%
B
3
71%
C
4
12%
D
6
9%
Solution:
[
Pt
(
Cl
)
(
p
y
)
(
N
H
3
)
(
N
H
2
O
H
)
]
+
is square planar complex. The structures are formed by fixing a group and then arranging all the groups.
Hence, this complex shows three geometrical isomers
