The number of geometric isomers possible for the complex [ CoL 2 Cl 2]-( L = H 2 NCH 2 CH 2 O -)is

Question

The number of geometric isomers possible for the complex [ CoL 2 Cl 2]-( L = H 2 NCH 2 CH 2 O -)is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

[ CoL 2 Cl 2]-( L = H 2 NCH 2 CH 2 O -) General form of complex is [ M ( AB )2 C 2] Total possible geometrical isomers are 5 <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/11aea60d5609cd3fa0555031347d8c3c-.png" />

Q. The number of geometric isomers possible for the complex $[C o L_{2} C l_{2}]^{-} (L = H_{2} NC H_{2} C H_{2} O^{-})$ is

$[C o L_{2} C l_{2}]^{-} (L = H_{2} NC H_{2} C H_{2} O^{-})$
General form of complex is $[M (A B)_{2} C_{2}]$
Total possible geometrical isomers are $5$

Q. The number of geometric isomers possible for the complex [CoL2​Cl2​]−(L=H2​NCH2​CH2​O−)is

[CoL2​Cl2​]−(L=H2​NCH2​CH2​O−) General form of complex is [M(AB)2​C2​] Total possible geometrical isomers are 5

Q. The number of geometric isomers possible for the complex $[C o L_{2} C l_{2}]^{-} (L = H_{2} NC H_{2} C H_{2} O^{-})$ is

$[C o L_{2} C l_{2}]^{-} (L = H_{2} NC H_{2} C H_{2} O^{-})$
General form of complex is $[M (A B)_{2} C_{2}]$
Total possible geometrical isomers are $5$