The number of electrons involved in the reduction of Cr2,O2-7 in acidic solution to Cr3+ is

Question

The number of electrons involved in the reduction of Cr2,O2-7 in acidic solution to Cr3+ is (A) 0 (B) 2 (C) 3 (D) 5

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/2359e66c536aea3b13b20c292a550ac1-.jpeg" /> In this reaction three electrons are required for the reduction of Cr2O2-7 into Cr3+.

Q. The number of electrons involved in the reduction of $C r_{2}, O_{7}^{2 -}$ in acidic solution to $C r^{3 +}$ is

$0$

$2$

$3$

$5$

In this reaction three electrons are required for the reduction of $C r_{2} O_{7}^{2 -}$ into $C r^{3 +}$ .

Q. The number of electrons involved in the reduction of Cr2​,O72−​ in acidic solution to Cr3+ is

0

2

3

5

In this reaction three electrons are required for the reduction of Cr2​O72−​ into Cr3+.

Q. The number of electrons involved in the reduction of $C r_{2}, O_{7}^{2 -}$ in acidic solution to $C r^{3 +}$ is

$0$

$2$

$3$

$5$

In this reaction three electrons are required for the reduction of $C r_{2} O_{7}^{2 -}$ into $C r^{3 +}$ .