The number of alkenes (including stereoisomers) which can produce 2-butanol by the successive treatment of (i) B2H6 in tetrahydrofuran solvent and (ii) alkaline H2O2 solution is/are

Question

The number of alkenes (including stereoisomers) which can produce 2-butanol by the successive treatment of (i) B2H6 in tetrahydrofuran solvent and (ii) alkaline H2O2 solution is/are (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Structure of butan-2-ol is CH3- undersetO H underset|.C H-CH2-CH3 Now, the simple format of HBO (hydroboration oxidant) reaction is R - CH = CH 2+ B 2 H 6 xrightarrow THF ( R - CH 2 CH 2)3 B xrightarrow H 2 O 2 / overline O H RCH 2 underset overset|OHCH 2 So, CH3-CH=CH-CH3 definitely an option as the mechanistic approach for the BH3 addition is as <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-22mipcnya7dd.png" /> ( CH 3 CH 2- CHCH 3)3 B xrightarrow H 2 O 2 / overline O H CH 3 CH 2- underset overset|OHCH CH 3 Now, CH3-CH=CH-CH3 can have both cis and trans-forms.

Q. The number of alkenes (including stereoisomers) which can produce 2-butanol by the successive treatment of (i) B2​H6​ in tetrahydrofuran solvent and (ii) alkaline H2​O2​ solution is/are

Q. The number of alkenes (including stereoisomers) which can produce 2-butanol by the successive treatment of (i) $B_{2} H_{6}$ in tetrahydrofuran solvent and (ii) alkaline $H_{2} O_{2}$ solution is/are