The number N = 6 log10 2 + log10 31, lies between two successive integers whose sum is equal to ,

Question

The number N = 6 log10 2 + log10 31, lies between two successive integers whose sum is equal to , (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

N = log10 64 + log10 31 = log10 1984 ∴ 3 < N < 4

Q. The number $N = 6 l o g_{10} 2 + l o g_{10} 31$ , lies between two successive integers whose sum is equal to ____ ,