The nitrogen gas pressure inside a container of volume 2.6 cm 3 is 2.3 atm at 27° C. The approximate number of moles of nitrogen present in the container is [R=0.0821 L. atm .mol -1 K -1]

Question

The nitrogen gas pressure inside a container of volume 2.6 cm 3 is 2.3 atm at 27° C. The approximate number of moles of nitrogen present in the container is [R=0.0821 L. atm .mol -1 K -1] (A) 4 × 10-3 (B) 1.7 × 10-4 (C) 4 × 10-4 (D) 2 × 10-4

Tardigrade Admin · Accepted Answer

Given, Pressure of N 2 gas =2.3 atm Volume =2.6 cm 3 =2.6 × 10-3 L Temperature =27° C +273 =300 K Gas constant (R)=0.0821 L atm mol -1 K -1 From, ideal gas equation p V=n R T n=(p V/R T) n =(2.3 atm × 2.6 × 10-3 L /0.0821 L atm mol -1 / K × 300 K ) n =2 × 10-4 mol

Q. The nitrogen gas pressure inside a container of volume $2.6 c m^{3}$ is $2.3$ atm at $2 7^{\circ} C$ . The approximate number of moles of nitrogen present in the container is $[R = 0.0821 L a t m m o l^{- 1} K^{- 1}]$

$4 \times 1 0^{- 3}$

$1.7 \times 1 0^{- 4}$

$4 \times 1 0^{- 4}$

$2 \times 1 0^{- 4}$

Q. The nitrogen gas pressure inside a container of volume 2.6cm3 is 2.3 atm at 27∘C. The approximate number of moles of nitrogen present in the container is [R=0.0821Latmmol−1K−1]

4×10−3

1.7×10−4

4×10−4

2×10−4

Given, Pressure of N2​ gas =2.3 atm Volume =2.6cm3 =2.6×10−3L Temperature =27∘C+273 =300K Gas constant (R)=0.0821L atm mol−1K−1 From, ideal gas equation pV=nRT n=RTpV​ n=0.0821Latmmol−1/K×300K2.3atm×2.6×10−3L​ n=2×10−4mol

Q. The nitrogen gas pressure inside a container of volume $2.6 c m^{3}$ is $2.3$ atm at $2 7^{\circ} C$ . The approximate number of moles of nitrogen present in the container is $[R = 0.0821 L a t m m o l^{- 1} K^{- 1}]$

$4 \times 1 0^{- 3}$

$1.7 \times 1 0^{- 4}$

$4 \times 1 0^{- 4}$

$2 \times 1 0^{- 4}$