The multiplicative inverse of the product of the additive inverse of x-1 and the multiplicative inverse of x2-1 is

Question

The multiplicative inverse of the product of the additive inverse of x-1 and the multiplicative inverse of x2-1 is (A) x+1 (B) -(x+1) (C) -(x2+1) (D) x2+1

Tardigrade Admin · Accepted Answer

The product =-(x-1) × (1/x2-1)=(-1/x+1) Its multiplicative inverse is -(x+1).

Q. The multiplicative inverse of the product of the additive inverse of $x - 1$ and the multiplicative inverse of $x^{2} - 1$ is

$x + 1$

$- (x + 1)$

$- (x^{2} + 1)$

$x^{2} + 1$

The product $= - (x - 1) \times \frac{1}{x ^{2} - 1} = \frac{- 1}{x + 1}$
Its multiplicative inverse is $- (x + 1)$ .

Q. The multiplicative inverse of the product of the additive inverse of x−1 and the multiplicative inverse of x2−1 is

x+1

−(x+1)

−(x2+1)

x2+1