The motion of a car on a banked road is shown in the figure. The centripetal force equation will be given by

Question

The motion of a car on a banked road is shown in the figure. The centripetal force equation will be given by (A) N sin θ+f cos θ=( mv 2/ R ) (B) f=( mv 2/ R ) (C) N cos θ+f=( mv 2/ R ) (D) N sin θ+f=( mv 2/ R )

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/8b6a3a3f1d817c2e64b185cf512ce77c-.png" /> Clearly form the figure, N sin θ and f cos θ contribute to the centripetal force. ∴ N sin θ + f cos θ = (mv2/R)

Q. The motion of a car on a banked road is shown in the figure. The centripetal force equation will be given by

$N sin θ + f cos θ = \frac{m v ^{2}}{R}$

$f = \frac{m v ^{2}}{R}$

$N cos θ + f = \frac{m v ^{2}}{R}$

$N sin θ + f = \frac{m v ^{2}}{R}$

Clearly form the figure, $N sin θ$ and $f cos θ$
contribute to the centripetal force.
$∴ N sin θ + f cos θ = \frac{m v ^{2}}{R}$

Q. The motion of a car on a banked road is shown in the figure. The centripetal force equation will be given by

Nsinθ+fcosθ=Rmv2​

f=Rmv2​

Ncosθ+f=Rmv2​

Nsinθ+f=Rmv2​

Clearly form the figure, Nsinθ and fcosθ contribute to the centripetal force. ∴Nsinθ+fcosθ=Rmv2​

$N sin θ + f cos θ = \frac{m v ^{2}}{R}$

$f = \frac{m v ^{2}}{R}$

$N cos θ + f = \frac{m v ^{2}}{R}$

$N sin θ + f = \frac{m v ^{2}}{R}$

Clearly form the figure, $N sin θ$ and $f cos θ$
contribute to the centripetal force.
$∴ N sin θ + f cos θ = \frac{m v ^{2}}{R}$