The most probable velocity (in cm/s) of hydrogen molecule at 27° C will be

Question

The most probable velocity (in cm/s) of hydrogen molecule at 27° C will be (A) 19.3 × 104 (B) 17.8 × 104 (C) 24.93 × 109 (D) 17.8 × 108

Tardigrade Admin · Accepted Answer

Most probable velocity is V mps =√(8 RT /π M ) beginarrayl R =8.314 T =27+273=300 K endarray M =2 g / mol molecular mass of hydrogen Most probable velocity will be √(8 × 8.314 × 300/3.14 × 2 × 10-3)=1782.50 m / s =17.8 × 104 cm / s

Q. The most probable velocity (in cm/s) of hydrogen molecule at $2 7^{\circ} C$ will be

$19.3 \times 1 0^{4}$

$17.8 \times 1 0^{4}$

$24.93 \times 1 0^{9}$

$17.8 \times 1 0^{8}$

Most probable velocity is $V_{m p s} = \frac{8 RT}{π M}$
$R = 8.314 T = 27 + 273 = 300 K$
$M = 2 g / m o l$ molecular mass of hydrogen
Most probable velocity will be $\frac{8 \times 8.314 \times 300}{3.14 \times 2 \times 1 0 ^{- 3}} = 1782.50 m / s = 17.8 \times 1 0^{4} c m / s$

Q. The most probable velocity (in cm/s) of hydrogen molecule at 27∘C will be

19.3×104

17.8×104

24.93×109

17.8×108