The moment of magnet is 0.1 text Am2 and the force acting on each pole in a uniform magnetic field of 0.36 oersted is 1.44× 10-4N . The distance between the poles of magnet is

Question

The moment of magnet is 0.1 text Am2 and the force acting on each pole in a uniform magnetic field of 0.36 oersted is 1.44× 10-4N . The distance between the poles of magnet is (A) 2.5 cm (B) 5.0 cm (C) 1.25cm (D) 1.17cm

Tardigrade Admin · Accepted Answer

Here, M=0.1 text Am2, B=0.36 forested =0.36× 10-4J, F=1.44× 10-4N As F=mB ∴ m=(F/B)=(1.44× 10-4/0.36× 10-4)=4 Am As M=m× 2l ∴ 2l=(M/m)=(0.1/4)m=2.5 m

Q. The moment of magnet is $0.1 A m^{2}$ and the force acting on each pole in a uniform magnetic field of 0.36 oersted is $1.44 \times 10^{- 4} N$ . The distance between the poles of magnet is

2.5 cm

5.0 cm

1.25cm

1.17cm

Here, $M = 0.1 A m^{2},$ $B = 0.36$ forested $= 0.36 \times 10^{- 4} J,$ $F = 1.44 \times 10^{- 4} N$ As $F = m B$ $∴$ $m = \frac{F}{B} = \frac{1.44 \times 10 ^{- 4}}{0.36 \times 10 ^{- 4}} = 4 A m$ As $M = m \times 2 l$ $∴$ $2 l = \frac{M}{m} = \frac{0.1}{4} m = 2.5 m$

Q. The moment of magnet is 0.1Am2 and the force acting on each pole in a uniform magnetic field of 0.36 oersted is 1.44×10−4N . The distance between the poles of magnet is