The moment of inertia of a body about a given axis is 1.2 kgm 2. Initially the body is at rest. In order to produce a rotational K E of 1500 joule an angular acceleration of 25 rad / s 2 must be applied about the axis for a duration of

Question

The moment of inertia of a body about a given axis is 1.2 kgm 2. Initially the body is at rest. In order to produce a rotational K E of 1500 joule an angular acceleration of 25 rad / s 2 must be applied about the axis for a duration of (A) 4 s (B) 2 s (C) 8 s (D) 10 s

Tardigrade Admin · Accepted Answer

K E=(1/2) I ω2 ⇒ K E=(1/2) I ω2 ⇒ ω=50 rad / s t=(ω/α)=(50/25)=2 s

Q. The moment of inertia of a body about a given axis is $1.2 k g m^{2}$ . Initially the body is at rest. In order to produce a rotational $K E$ of $1500$ joule an angular acceleration of $25 r a d / s^{2}$ must be applied about the axis for a duration of

4 s

2 s

8 s

10 s

$K E = \frac{1}{2} I ω^{2} \Rightarrow K E = \frac{1}{2} I ω^{2}$
$\Rightarrow ω = 50 r a d / s t = \frac{ω}{α} = \frac{50}{25} = 2 s$

Q. The moment of inertia of a body about a given axis is 1.2kgm2. Initially the body is at rest. In order to produce a rotational KE of 1500 joule an angular acceleration of 25rad/s2 must be applied about the axis for a duration of

4 s

2 s

8 s

10 s

KE=21​Iω2⇒KE=21​Iω2 ⇒ω=50rad/s t=αω​=2550​=2s

Q. The moment of inertia of a body about a given axis is $1.2 k g m^{2}$ . Initially the body is at rest. In order to produce a rotational $K E$ of $1500$ joule an angular acceleration of $25 r a d / s^{2}$ must be applied about the axis for a duration of

$K E = \frac{1}{2} I ω^{2} \Rightarrow K E = \frac{1}{2} I ω^{2}$
$\Rightarrow ω = 50 r a d / s t = \frac{ω}{α} = \frac{50}{25} = 2 s$