The molecular size of ICl and Br2 is approximately same, but boiling point of ICl is about 40° higher than that of Br2. It is because

Question

The molecular size of ICl and Br2 is approximately same, but boiling point of ICl is about 40° higher than that of Br2. It is because (A) ICl bond is stronger than Br - Br bond (B) I.E. of I < I.E. of Br (C) ICl is polar while Br2 is non-polar (D) I has larger size than Br

Tardigrade Admin · Accepted Answer

Polar molecules also have dipole-dipole interactions which increase the boiling point

Q. The molecular size of $I Cl$ and $B r_{2}$ is approximately same, but boiling point of $I Cl$ is about $4 0^{\circ}$ higher than that of $B r_{2}$ . It is because

$I Cl$ bond is stronger than $B r - B r$ bond

$I . E .$ of $I < I . E$ . of $B r$

$I Cl$ is polar while $B r_{2}$ is non-polar

$I$ has larger size than $B r$

Polar molecules also have dipole-dipole interactions which increase the boiling point

Q. The molecular size of ICl and Br2​ is approximately same, but boiling point of ICl is about 40∘ higher than that of Br2​. It is because

ICl bond is stronger than Br−Br bond

I.E. of I<I.E. of Br

ICl is polar while Br2​ is non-polar

I has larger size than Br

Polar molecules also have dipole-dipole interactions which increase the boiling point

Q. The molecular size of $I Cl$ and $B r_{2}$ is approximately same, but boiling point of $I Cl$ is about $4 0^{\circ}$ higher than that of $B r_{2}$ . It is because

$I Cl$ bond is stronger than $B r - B r$ bond

$I . E .$ of $I < I . E$ . of $B r$

$I Cl$ is polar while $B r_{2}$ is non-polar

$I$ has larger size than $B r$