Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
The molecular mass of sucrose ( C 12 H 22 O 11) is
Q. The molecular mass of sucrose
(
C
12
H
22
O
11
)
is
1291
185
TS EAMCET 2020
Report Error
A
312 g
B
355 g
C
342 g
D
308 g
Solution:
Molecular mass of sucrose
(
C
12
H
22
O
11
)
is
=
12
×
12
+
22
×
1
+
11
×
16
=
342
g