The molecular formula of a non-stoichiometric tin oxide containing Sn (II) and Sn (IV) ions is Sn4.44O8. Therefore, the molar ratio of Sn (II) to Sn (IV) is approximately

Question

The molecular formula of a non-stoichiometric tin oxide containing Sn (II) and Sn (IV) ions is Sn4.44O8. Therefore, the molar ratio of Sn (II) to Sn (IV) is approximately (A) 1: 8 (B) 1: 6 (C) 1: 4 (D) 1: 1

Tardigrade Admin · Accepted Answer

Let in one mole of the given substance the number of moles of

S n

(II)

= x

moles and number of moles of

S n (I V) = y

moles.

∴ x + y = 4.44 and 2 x + 4 y = 16

By solving

x = 0.88

and

y = 3.56

∴

mole ratio of

S n

II to

S n

IV is

0.247 : 1 ≃ 1 : 4

Q. The molecular formula of a non-stoichiometric tin oxide containing Sn (II) and Sn (IV) ions is $S n_{4.44} O_{8} .$

Therefore, the molar ratio of Sn (II) to Sn (IV) is approximately

1 : 8

1 : 6

1 : 4

1 : 1

Let in one mole of the given substance the number of moles of $S n$ (II) $= x$ moles and number of moles of $S n (I V) = y$ moles.
$∴ x + y = 4.44 and 2 x + 4 y = 16$
By solving $x = 0.88$ and $y = 3.56$
$∴$ mole ratio of $S n$ II to $S n$ IV is $0.247 : 1 ≃ 1 : 4$

Q. The molecular formula of a non-stoichiometric tin oxide containing Sn (II) and Sn (IV) ions is Sn4.44​O8​. Therefore, the molar ratio of Sn (II) to Sn (IV) is approximately