The molarity of a solution obtained by mixing 800 mL of 0.5 M HCl with 200 mL of 1 M HCl will be

Question

The molarity of a solution obtained by mixing 800 mL of 0.5 M HCl with 200 mL of 1 M HCl will be (A) 0.8 M (B) 0.6 M (C) 0.4 M (D) 0.2 M

Tardigrade Admin · Accepted Answer

Given,: M1=0.5 M , M2=1 M , V1=800 mL , V2=200 mL V3=V1+V2=800+200=1000 mL M1 V1+M2 V2=M3 V3 ⇒ 0.5 × 800+1 × 200=M3 × 1000 M3=(0.5 × 800+1 × 200/1000) =(600/1000)=0.6 M

Q. The molarity of a solution obtained by mixing 800mL of 0.5MHCl with 200mL of 1MHCl will be

0.8 M

0.6 M

0.4 M

0.2 M

Given, :M1​=0.5M,M2​=1M, V1​=800mL,V2​=200mL V3​=V1​+V2​=800+200=1000mL M1​V1​+M2​V2​=M3​V3​ ⇒0.5×800+1×200=M3​×1000 M3​=10000.5×800+1×200​ =1000600​=0.6M

Q. The molarity of a solution obtained by mixing $800 m L$ of $0.5 M H Cl$ with $200 m L$ of $1 M H Cl$ will be