The molar solubility [.in mol L- 1]. of a sparingly soluble salt MX4 is ‘s’. The corresponding solubility product is Ksp.s is given in terms of Ksp by the relation

Question

The molar solubility [.in mol L- 1]. of a sparingly soluble salt MX4 is ‘s’. The corresponding solubility product is Ksp.s is given in terms of Ksp by the relation (A) s=((K s p/256))1 / 5 (B) s=(128 K s p)1 / 4 (C) s=((K s p/128))1 / 6 (D) s=(256 K s p)1 / 5

Tardigrade Admin · Accepted Answer

For the solute textAxBy oversetleftharpoons textxA + textyB Ksp=xxyy(s)x + y textMX4 oversetleftharpoons textM4 + + 4 textX- x = 1, y = 4 Ksp=(4)4(1)1(s)5=256s5 s=((K s p/256))1 / 5

Q. The molar solubility $[in m o l L^{- 1}]$ of a sparingly soluble salt $M X_{4}$ is ‘s’. The corresponding solubility product is Ksp.s is given in terms of Ksp by the relation

$s = (\frac{Ks p}{256})^{1/5}$

$s = (128 Ks p)^{1/4}$

$s = (\frac{Ks p}{128})^{1/6}$

$s = (256 Ks p)^{1/5}$

For the solute $AxBy ⇌ xA + yB$
$Ks p = x^{x} y^{y} (s)^{x + y}$
$MX_{4} ⇌ M^{4 +} + 4 X^{-}$
x = 1, y = 4
$Ks p = (4)^{4} (1)^{1} (s)^{5} = 256 s^{5}$
$s = (\frac{Ks p}{256})^{1/5}$

Q. The molar solubility [inmolL−1] of a sparingly soluble salt MX4​ is ‘s’. The corresponding solubility product is Ksp.s is given in terms of Ksp by the relation

s=(256Ksp​)1/5

s=(128Ksp)1/4

s=(128Ksp​)1/6

s=(256Ksp)1/5