Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Physics
The molar heat capacity of a monoatomic ideal gas undergoing the process PV1 / 2=constant is
Q. The molar heat capacity of a monoatomic ideal gas undergoing the process
P
V
1/2
=
co
n
s
t
an
t
is
2522
164
NTA Abhyas
NTA Abhyas 2020
Report Error
A
2
15
R
B
2
23
R
C
2
7
R
D
Zero
Solution:
For a polytropic process, specific heat of an ideal gas is given by,
c
=
γ
−
1
R
+
1
−
n
R
[
n
=
2
1
,
f
or
t
hi
s
p
o
l
y
t
ro
p
i
c
p
rocess
]
c
=
3
5
−
1
R
+
2
R
=
2
3
R
+
2
R
=
2
7
R