The molar conductance of NaCl , HCl and CH 3 COONa at infinite dilution are 126.45,426.16 and 91.0 S cm 2 mol -1 respectively. The molar conductance of CH 3 COOH at infinite dilution is. Choose the right option for your answer.

Question

The molar conductance of NaCl , HCl and CH 3 COONa at infinite dilution are 126.45,426.16 and 91.0 S cm 2 mol -1 respectively. The molar conductance of CH 3 COOH at infinite dilution is. Choose the right option for your answer. (A) 201.28 S cm 2 mol -1 (B) 390.71 S cm 2 mol -1 (C) 698.28 S cm 2 mol -1 (D) 540.48 S cm 2 mol -1

Tardigrade Admin · Accepted Answer

λ M CH 3 COOH =λ CH 3 COO- M +λ Na + M +λ H + M +λ Cl- M -λ Na + M -λCl- M =λ CH 3 COONa M +λ HCl M -λ NaCl M =91+426.16-126.45 =390.71 S cm 2 mole -1

Q. The molar conductance of $N a Cl, H Cl$ and $C H_{3} COON a$ at infinite dilution are $126.45, 426.16$ and $91.0 S c m^{2} m o l^{- 1}$ respectively. The molar conductance of $C H_{3} COO H$ at infinite dilution is. Choose the right option for your answer.

$201.28 S c m^{2} m o l^{- 1}$

$390.71 S c m^{2} m o l^{- 1}$

$698.28 S c m^{2} m o l^{- 1}$

$540.48 S c m^{2} m o l^{- 1}$

$λ_{M}^{C H_{3} COO H} = λ_{C H_{3} CO O^{-}}^{M} + λ_{N a^{+}}^{M} + λ_{H^{+}}^{M} + λ_{C l^{-}}^{M} - λ_{N a^{+}}^{M} - λ_{C l^{-}}^{M}$
$= λ_{C H_{3} COON a}^{M} + λ_{H Cl}^{M} - λ_{N a Cl}^{M}$
$= 91 + 426.16 - 126.45$
$= 390.71 S c m^{2} m o l e^{- 1}$

Q. The molar conductance of NaCl,HCl and CH3​COONa at infinite dilution are 126.45,426.16 and 91.0Scm2mol−1 respectively. The molar conductance of CH3​COOH at infinite dilution is. Choose the right option for your answer.

201.28Scm2mol−1

390.71Scm2mol−1

698.28Scm2mol−1

540.48Scm2mol−1