The molality of the solution prepared by dissolving 125 mL of pure methanol ( d =0.8 gmL -1) in 375 g of ethanol is:

Question

The molality of the solution prepared by dissolving 125 mL of pure methanol ( d =0.8 gmL -1) in 375 g of ethanol is: (A) 10.8 (B) 11.2 (C) 8.33 (D) 10.4

Tardigrade Admin · Accepted Answer

m =(125 × 0.8 × 1000/32 × 375)=8.33

Q. The molality of the solution prepared by dissolving 125 $m L$ of pure methanol $(d = 0.8 g m L^{- 1})$ in $375 g$ of ethanol is:

10.8

11.2

8.33

10.4

$m = \frac{125 \times 0.8 \times 1000}{32 \times 375} = 8.33$

Q. The molality of the solution prepared by dissolving 125 mL of pure methanol (d=0.8gmL−1) in 375g of ethanol is:

10.8

11.2

8.33

10.4

m=32×375125×0.8×1000​=8.33

Q. The molality of the solution prepared by dissolving 125 $m L$ of pure methanol $(d = 0.8 g m L^{- 1})$ in $375 g$ of ethanol is:

$m = \frac{125 \times 0.8 \times 1000}{32 \times 375} = 8.33$