The molal elevation constant of water is 0.52 kg mol -1, The boiling point of 1.0 molal aqueous KCl solution (assuming complete dissociation of KCl ), should be

Question

The molal elevation constant of water is 0.52 kg mol -1, The boiling point of 1.0 molal aqueous KCl solution (assuming complete dissociation of KCl ), should be (A) 98.96° C (B) 100.52° C (C) 101.04° C (D) 104.01° C

Tardigrade Admin · Accepted Answer

i=2( KCl arrow K prime+ Cl ) Δ Tb=i Kb m=2 × 0.52 × 1=1.04 ∴ Tb=101.04° C

Q. The molal elevation constant of water is $0.52 k g m o l^{- 1}$ , The boiling point of $1.0$ molal aqueous $K Cl$ solution (assuming complete dissociation of $K Cl$ ), should be

$98.9 6^{\circ} C$

$100.5 2^{\circ} C$

$101.0 4^{\circ} C$

$104.0 1^{\circ} C$

$i = 2 (K Cl \to K^{'} + Cl)$
$Δ T_{b} = i K_{b} m = 2 \times 0.52 \times 1 = 1.04$
$∴ T_{b} = 101.0 4^{\circ} C$

Q. The molal elevation constant of water is 0.52kgmol−1, The boiling point of 1.0 molal aqueous KCl solution (assuming complete dissociation of KCl ), should be

98.96∘C

100.52∘C

101.04∘C

104.01∘C