The minimum values of uncertainties involved in the determination of both the position and velocity of a particle are respectively 1 × 10-10m and 1 × 10-10 ms-1. Then, the mass (in kg) of the particle is

Question

The minimum values of uncertainties involved in the determination of both the position and velocity of a particle are respectively 1 × 10-10m and 1 × 10-10 ms-1. Then, the mass (in kg) of the particle is (A) 5.270 × 10-15 (B) 5.270 × 10-20 (C) 5.270 × 10-16 (D) 5.270 × 10-10

Tardigrade Admin · Accepted Answer

Given uncertainty in position =1 × 10-10 m Uncertainty in velocity =1 × 10-10 m / s From equation m × Δ v × Δ x ≈ (h/4 π) So, m =(h/4 π × Δ x × Δ v) =(6.62 .6 × 10-31/4 × 3.14 × 10-10 × 10-10) Mass (m)=5.27 × 10-15 kg

Q. The minimum values of uncertainties involved in the determination of both the position and velocity of a particle are respectively $1 \times 1 0^{- 10} m$ and $1 \times 1 0^{- 10} m s^{- 1}$ . Then, the mass (in kg) of the particle is

$5.270 \times 1 0^{- 15}$

$5.270 \times 1 0^{- 20}$

$5.270 \times 1 0^{- 16}$

$5.270 \times 1 0^{- 10}$

$5.270 \times 1 0^{- 14}$

Q. The minimum values of uncertainties involved in the determination of both the position and velocity of a particle are respectively 1×10−10m and 1×10−10ms−1. Then, the mass (in kg) of the particle is

5.270×10−15

5.270×10−20

5.270×10−16

5.270×10−10

5.270×10−14