The minimum value of the function max (x, x2) is equal to

Question

The minimum value of the function max (x, x2) is equal to (A) 0 (B) 1 (C) 2 (D) 1/2

Tardigrade Admin · Accepted Answer

Let f(x)= max x, x2 <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/e18cfb0e9d1d645ffbbdf1690589554d-.png" /> ∴ Minimum value of f(x)=0.

Q. The minimum value of the function max $(x, x^{2})$ is equal to

0

1

2

1/2

3/2

Let $f (x) = max {x, x^{2}}$

$∴$ Minimum value of $f (x) = 0$ .

Q. The minimum value of the function max (x,x2) is equal to

0

1

2

1/2

3/2

Let f(x)=max{x,x2} ∴ Minimum value of f(x)=0.

Q. The minimum value of the function max $(x, x^{2})$ is equal to

Let $f (x) = max {x, x^{2}}$

$∴$ Minimum value of $f (x) = 0$ .