Question

The metal with the highest oxidation state present in $K_{2}Cr{O}_4,NbC{l}_5$ and $Mn{O}_2$ is

• A. Nb
• B. Mn
• C. K
• D. Cr

Answer 1

Answer: (D)

Let the oxidation state of metals in given compounds be $x$.
(i) $K_{2}Cr{O}_4$
$2\left(+1\right)+x+4\left(-2\right)=0$
$x=8-2=+6$
The oxidation state of $K$ is $K_{2}Cr{O}_{4}is+6$.
(ii)$NbC{l}_5$
$x+5\left(-1\right)=0$
$x=+5$
Oxidation state of $Nb$ in $NbC{l}_5$ is $+5$.
(iii)$Mn{O}_2$
$x+2\left(-2\right)=0$
$x=+4$
Oxidation state of $Mn$ is $Mn{O}_2$ is +4.
Thus, $Cr$ has the highest oxidation state $(+6)$ among the given metals.