The mean free path for a gas, with molecular diameter d and number density n can be expressed as :

Question

The mean free path for a gas, with molecular diameter d and number density n can be expressed as : (A)  (1/√2 n π d) (B)  (1/√2 n π d2) (C)  (1/√2 n2 π d2) (D)  (1/√2 n2 π2 d2)

Tardigrade Admin · Accepted Answer

Mean free path for a gas sample λm=(1/√2π d2 n) where d is diameter of a gas molecule and n is molecular density

Q. The mean free path for a gas, with molecular diameter $d$ and number density $n$ can be expressed as :

$\frac{1}{2 nπ d}$

$\frac{1}{2 nπ d ^{2}}$

$\frac{1}{2 n ^{2} π d ^{2}}$

$\frac{1}{2 n ^{2} π ^{2} d ^{2}}$

Mean free path for a gas sample $λ_{m} = \frac{1}{2 π d ^{2} n}$
where d is diameter of a gas molecule and n is molecular density

Q. The mean free path for a gas, with molecular diameter d and number density n can be expressed as :

2​nπd1​

2​nπd21​

2​n2πd21​

2​n2π2d21​