The maximum velocity of a particle, executing simple harmonic motion with an amplitude 7 mm is 4.4 m s- 1 . The period of oscillation is

Question

The maximum velocity of a particle, executing simple harmonic motion with an amplitude 7 mm is 4.4 m s- 1 . The period of oscillation is (A) 100 s (B) 0.01 s (C) 10 s (D) 0.1 s

Tardigrade Admin · Accepted Answer

Maximum velocity (ν) textm= textaω = texta((2 π / textT)) ∴ textT=(2 π texta/(ν) textm)=2× (22/7)× ((7 × ( text10)- 3)/4 ⋅ 4) T=10- 2=0.01 s

Q. The maximum velocity of a particle, executing simple harmonic motion with an amplitude $7 mm$ is $4.4 m s^{- 1}$ . The period of oscillation is

$100 s$

$0.01 s$

$10 s$

$0.1 s$

Maximum velocity $(ν)_{m} = a ω = a (\frac{2 π}{T})$
$∴$ $T = \frac{2 π a}{( ν ) _{m}} = 2 \times \frac{22}{7} \times \frac{( 7 \times ( 10 ) ^{- 3} )}{4 \cdot 4}$
$T = 1 0^{- 2} = 0.01 s$

Q. The maximum velocity of a particle, executing simple harmonic motion with an amplitude 7mm is 4.4ms−1 . The period of oscillation is

100s

0.01s

10s

0.1s