Question

The maximum value of $z=5x+2y$, subject to the constraints $x+y\le 7,x+2y\le 10,x,y\ge 0$ is

• A. 10
• B. 26
• C. 35
• D. 70

Answer 1

Answer: (C)

Change the inequalities into equations and draw the graph of lines, thus we get the required feasible region.
The region bounded by the vertices $A(0,5),B(4,3)$ and $C(7,0).$
The objective function is maximum at $C(7,0)$ and Max $z=5\times 7+2\times 0=35.$