Q.
The mass of deuteron (1H2) nucleus is 2.014103u. If the masses of proton and neutron are 1.007275u and 1.007275u respectively, calculate the binding energy per nucleon.
Here, mp=1.007275m:mn=1.008667u and mass of _1H2 nucleus, mN(HH2)=2.0159403u. The deuteron nucleus contains one proton and one neutron. Therefore, mass of nucleons constituting deuteron, mp+mn=1.007275+ 1.008665=2.015940u.
Therefore, mass defect, Δm=(mp+mn)−mN(_1H2) =2.01540−2.013553=0.002387u
Packing fraction, AΔm=20.002387=0.0011935u.