Q.
The mass of CaCO3 is required to react with 25 mL of 0.75 M HCl is
3814
262
Some Basic Concepts of Chemistry
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Solution:
CaCO3+2HCl→CaCl2+CO2+H2 25mL of 0.75MHCl =10025L×(0.75molL−1) =0.01875mol
Moles of CaCO3 required =2Moles of HCl =20.01875=9.375×10−3mol
Mass of CaCO3 required =9.375×10−3mol×100gmol−1 =0.9375g=0.94g