Question

The mass of 112 $c{m}^3$ of $C{H}_4$ gas at STP is

• A. 0.16 g
• B. 0.8 g
• C. 0.08 g
• D. 1.6 g

Answer 1

Answer: (C)

The mass of $112c{m}^3$ of $C{H}_4$ at $S.T.P.$
$=\frac{16\times 112}{22400}=0.08g$