The mass and volume of a body are found to be 5. 00 ± 0.05 kg and 1.00 ± 0.05 m3 respectively. Then the maximum possible percentage error in its density is

Question

The mass and volume of a body are found to be 5. 00 ± 0.05 kg and 1.00 ± 0.05 m3 respectively. Then the maximum possible percentage error in its density is (A) 6% (B) 3% (C) 10% (D) 5%

Tardigrade Admin · Accepted Answer

(Δ ρ /ρ )=(Δ m/m)+(Δ V/V) =(0.05/5)× 100+(0.05/1)× 100=6 (Δ ρ /ρ )=6%

Q. The mass and volume of a body are found to be $5. 00 \pm 0.05 k g$ and $1.00 \pm 0.05 m^{3}$ respectively. Then the maximum possible percentage error in its density is

6%

3%

10%

5%

7%

$\frac{Δ ρ}{ρ} = \frac{Δ m}{m} + \frac{Δ V}{V}$
$= \frac{0.05}{5} \times 100 + \frac{0.05}{1} \times 100 = 6$
$\frac{Δ ρ}{ρ} = 6$

Q. The mass and volume of a body are found to be 5.00±0.05kg and 1.00±0.05m3 respectively. Then the maximum possible percentage error in its density is

6%

3%

10%

5%

7%

ρΔρ​=mΔm​+VΔV​ =50.05​×100+10.05​×100=6 ρΔρ​=6

Q. The mass and volume of a body are found to be $5. 00 \pm 0.05 k g$ and $1.00 \pm 0.05 m^{3}$ respectively. Then the maximum possible percentage error in its density is

$\frac{Δ ρ}{ρ} = \frac{Δ m}{m} + \frac{Δ V}{V}$
$= \frac{0.05}{5} \times 100 + \frac{0.05}{1} \times 100 = 6$
$\frac{Δ ρ}{ρ} = 6$