The magnetic force on a point charge is vecF=q( vecv× vecB) Here, q= electric charge vecv= velocity of point charge vecB= magnetic field The dimensions of vecB is:

Question

The magnetic force on a point charge is vecF=q( vecv× vecB) Here, q= electric charge vecv= velocity of point charge vecB= magnetic field The dimensions of vecB is: (A)  [MLT-1A]  (B)  [M2LT-2A-1]  (C)  [MT-2A-1]  (D) none of these

Tardigrade Admin · Accepted Answer

vecF=q vecv × vecB or F=q v B sin θ ∴ [B] =[(F/q v)]=(M L T-2/[A T][L T-1]) =[M T-2 A-1]

Q. The magnetic force on a point charge is $F = q (v \times B)$ Here, $q =$ electric charge $v =$ velocity of point charge $B =$ magnetic field The dimensions of $B$ is:

$[M L T^{- 1} A]$

$[M^{2} L T^{- 2} A^{- 1}]$

$[M T^{- 2} A^{- 1}]$

none of these

$F = q v \times B$
or $F = q v B sin θ$
$∴ [B] = [\frac{F}{q v}] = \frac{M L T ^{- 2}}{[ A T ] [ L T ^{- 1} ]}$
$= [M T^{- 2} A^{- 1}]$

Q. The magnetic force on a point charge is F=q(v×B) Here, q= electric charge v= velocity of point charge B= magnetic field The dimensions of B is:

[MLT−1A]

[M2LT−2A−1]

[MT−2A−1]