The magnetic flux through a loop of resistance 10 Ω is given by φ = 5t2 - 4t + 1 Weber. How much current is induced in the loop after 0.2 sec ?

Question

The magnetic flux through a loop of resistance 10 Ω is given by φ = 5t2 - 4t + 1 Weber. How much current is induced in the loop after 0.2 sec ? (A) 0.4 A (B) 0.2 A (C) 0.14 A (D) 0.02 A

Tardigrade Admin · Accepted Answer

The flux is given by φ=5 t2-4 t+1. The emf induced in the resistance would be equal to e=-(d φ/d t)=10 t-4 Thus, the current induced in the loop is equal to i=(e/R)=-((10 t-4/10)) at t=0.2 s, we have i=-((10 × 0.2-4/10)) =(2/10)=0.2 A

Q. The magnetic flux through a loop of resistance 10Ω is given by ϕ=5t2−4t+1 Weber. How much current is induced in the loop after 0.2 sec ?

0.4 A

0.2 A

0.14 A

0.02 A

The flux is given by ϕ=5t2−4t+1. The emf induced in the resistance would be equal to e=−dtdϕ​=10t−4 Thus, the current induced in the loop is equal to i=Re​=−(1010t−4​) at t=0.2s, we have i=−(1010×0.2−4​) =102​=0.2A

Q. The magnetic flux through a loop of resistance $10 Ω$ is given by $ϕ = 5 t^{2} - 4 t + 1$ Weber. How much current is induced in the loop after $0.2$ sec ?