The magnetic flux through a coil perpendicular to its plane is varying according to the relation φ=(5 t3+4 t+2 t-5) Weber. If the resistant of the coil is 5 ohm, then the induced current through the coil at t =2 sec will be:

Question

The magnetic flux through a coil perpendicular to its plane is varying according to the relation φ=(5 t3+4 t+2 t-5) Weber. If the resistant of the coil is 5 ohm, then the induced current through the coil at t =2 sec will be: (A) 15.6 A (B) 16.6 A (C) 17.6 A (D) 18.6 A

Tardigrade Admin · Accepted Answer

φ=5 t 3+4 t 2+2 t -5 | e |=( d φ/ dt )=15 t 2+8 t +2 At t =2,| e |=15 × 22+8 × 2+2 ⇒ e =78 V ⇒ I =( e / R )=(78/5)=15.60

Q. The magnetic flux through a coil perpendicular to its plane is varying according to the relation $ϕ = (5 t^{3} + 4 t + 2 t - 5)$ Weber. If the resistant of the coil is $5 o hm$ , then the induced current through the coil at $t = 2 sec$ will be:

15.6 A

16.6 A

17.6 A

18.6 A

$ϕ = 5 t^{3} + 4 t^{2} + 2 t - 5$
$∣ e ∣ = \frac{d ϕ}{d t} = 15 t^{2} + 8 t + 2$
At $t = 2, ∣ e ∣ = 15 \times 2^{2} + 8 \times 2 + 2$
$\Rightarrow e = 78 V$
$\Rightarrow I = \frac{e}{R} = \frac{78}{5} = 15.60$

Q. The magnetic flux through a coil perpendicular to its plane is varying according to the relation ϕ=(5t3+4t+2t−5) Weber. If the resistant of the coil is 5ohm, then the induced current through the coil at t=2sec will be: