The magnetic flux density B at a distance r from a long straight wire carrying a steady current varies with r as shown in figure

Question

The magnetic flux density B at a distance r from a long straight wire carrying a steady current varies with r as shown in figure (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/119454057ac2e99018d5ff4899697692-.png" /> The magnetic field due to a long wire carrying current I, at a distance r is given by B=(μ0/2 π) (I/r) ⇒ B propto (1/r) Since B is inversely proportional to r,

Q. The magnetic flux density $B$ at a distance $r$ from a long straight wire carrying a steady current varies with $r$ as shown in figure

The magnetic field due to a long wire carrying current $I$ , at a distance $r$ is given by
$B = \frac{μ _{0}}{2 π} \frac{I}{r}$
$\Rightarrow B \propto \frac{1}{r}$
Since $B$ is inversely proportional to $r$ ,

Q. The magnetic flux density B at a distance r from a long straight wire carrying a steady current varies with r as shown in figure

The magnetic field due to a long wire carrying current I, at a distance r is given by B=2πμ0​​rI​ ⇒B∝r1​ Since B is inversely proportional to r,

Q. The magnetic flux density $B$ at a distance $r$ from a long straight wire carrying a steady current varies with $r$ as shown in figure

The magnetic field due to a long wire carrying current $I$ , at a distance $r$ is given by
$B = \frac{μ _{0}}{2 π} \frac{I}{r}$
$\Rightarrow B \propto \frac{1}{r}$
Since $B$ is inversely proportional to $r$ ,