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Question
Physics
The magnetic field at P on the axis of a solenoid having 100 turn/ m and carrying a current of 5 A is
Q. The magnetic field at
P
on the axis of a solenoid having
100
turn/
m
and carrying a current of
5
A
is
2183
223
AIIMS
AIIMS 2011
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A
250
μ
0
B
500
2
μ
0
C
500
μ
0
D
250
2
μ
0
Solution:
The magnetic field at
P
is
B
=
2
μ
0
n
I
(
cos
θ
+
cos
θ
)
where
n
is number of turns,
I
the current.
Given,
n
=
100
,
I
=
5
A
and
θ
=
4
5
∘
∴
B
=
2
μ
0
×
100
×
5
×
2
2
⇒
B
=
250
2
μ
0