The magnetic field amplitude of an electromagnetic wave is 2× 10-7T , Its electric field amplitude, if the wave is travelling in free space is:

Question

The magnetic field amplitude of an electromagnetic wave is 2× 10-7T , Its electric field amplitude, if the wave is travelling in free space is: (A)  6 Vm-1  (B)  60 Vm-1  (C)  (1/6) Vm-1  (D) none of these

Tardigrade Admin · Accepted Answer

We can write the electric and magnetic fields as sinusoidal functions of position

x

and time

t

.

E = E_{0} sin (k x - ω t)

B = B_{0} sin (k x - ω t)

In this

E_{0}

and

B_{0}

are the amplitudes of the fields. Further

c = \frac{E _{0}}{B _{0}}

E_{0} = B_{0} c

Given,

B_{0} = 2 \times 1 0^{- 7} T

,

c = 3 \times 1 0^{8} m / s

we have

E_{0} = 2 \times 1 0^{- 7} \times 3 \times 1 0^{8}

= 60 V m^{- 1}

Q. The magnetic field amplitude of an electromagnetic wave is $2 \times 10^{- 7} T$ , Its electric field amplitude, if the wave is travelling in free space is:

$6 V m^{- 1}$

$60 V m^{- 1}$

$\frac{1}{6} V m^{- 1}$

none of these

Q. The magnetic field amplitude of an electromagnetic wave is 2×10−7T , Its electric field amplitude, if the wave is travelling in free space is:

6Vm−1

60Vm−1

61​Vm−1

none of these

Q. The magnetic field amplitude of an electromagnetic wave is $2 \times 10^{- 7} T$ , Its electric field amplitude, if the wave is travelling in free space is:

$6 V m^{- 1}$

$60 V m^{- 1}$

$\frac{1}{6} V m^{- 1}$