Let the point be (h,k)
Now equation of tangent to the parabola y2=4ax whose slope is m is y=mx+ma
as it passes through (h,k) ∴k=mh+ma⇒m2h−mk+a=0
It has two roots m1,2m1 ∴m1+2m1=hk,2m1⋅m1=ha m1=3hk… (i) m12=2ha… (ii) from (i) & (ii) ⇒(3h)2k2=2ha⇒k2=29ah
Thus locus of point is y2=29ax.