The length of one turn of the helix in a B- form DNA is approximately-

Question

The length of one turn of the helix in a B- form DNA is approximately- (A) 0.34 nm (B) 20 nm (C) 2 nm (D) 3.4 nm

Tardigrade Admin · Accepted Answer

B-form of DNA shows right handed coiling which contains 10 base pairs in each turn. One complete turn of DNA occupies 34 mathringA distance so in nm it will 3.4 nm because 1 nm =10-9 m 1 mathringA=10-10 m 34 mathringA=34 × 10-10 m or =3.4 × 10-9 m So, =3.4 nm.

Q. The length of one turn of the helix in a B- form DNA is approximately-

0.34 nm

20 nm

2 nm

3.4 nm

B-form of DNA shows right handed coiling which contains 10 base pairs in each turn. One complete turn of DNA occupies 34A˚ distance so in nm it will 3.4nm because 1nm=10−9m 1A˚=10−10m 34A˚=34×10−10m or =3.4×10−9m So, =3.4nm.

Q. The length of one turn of the helix in a $B$ - form DNA is approximately-