The length of one rod ℓ1=3.323 cm and the other is ℓ2=3.321 cm. Both rods were measured with one measuring instrument with least count 0.001 cm Then (ℓ1-ℓ2) is

Question

The length of one rod ℓ1=3.323 cm and the other is ℓ2=3.321 cm. Both rods were measured with one measuring instrument with least count 0.001 cm Then (ℓ1-ℓ2) is (A) (0.002 ± 0.001) cm (B) (0.002 ± 0.000) cm (C) (0.002 ± 0.002) cm (D) None of these

Tardigrade Admin · Accepted Answer

ℓ1-ℓ2=(3.323 ± 0.001)-(3.321 ± 0.001) =(0.002 ± 0.002) cm

Q. The length of one rod $ℓ_{1} = 3.323 c m$ and the other is $ℓ_{2} = 3.321 c m$ . Both rods were measured with one measuring instrument with least count $0.001 c m$ Then $(ℓ_{1} - ℓ_{2})$ is

$(0.002 \pm 0.001) c m$

$(0.002 \pm 0.000) c m$

$(0.002 \pm 0.002) c m$

None of these

$ℓ_{1} - ℓ_{2} = (3.323 \pm 0.001) - (3.321 \pm 0.001)$
$= (0.002 \pm 0.002) c m$

Q. The length of one rod ℓ1​=3.323cm and the other is ℓ2​=3.321cm. Both rods were measured with one measuring instrument with least count 0.001cm Then (ℓ1​−ℓ2​) is

(0.002±0.001)cm

(0.002±0.000)cm

(0.002±0.002)cm