Question

The length $I$, breadth $b$ and thickness $t$ of a block of wood were measured with the help of a measuring scale. The results with permissible errors are $l=(15.12\pm 0.01)cm$, $b=(10.15\pm 0.01)cm$, $t=(5.28\pm 0.01)cm$. The percentage error in its volume upto proper significant figures is

• A. $0.28\%$
• B. $0.36\%$
• C. $0.48\%$
• D. $0.64\%$

Answer 1

Answer: (B)

Percentage error in volume
$=\frac{\Delta l}{l}\times 100+\frac{\Delta b}{b}\times 100+\frac{\Delta t}{t}\times 100$
$=\frac{0.01}{15.12}\times 100+\frac{0.01}{10.15}\times 100+\frac{0.01}{5.28}\times 100$
$=0.07\%+0.10\%+0.19\%$
$=0.36\%$