The LCM of polynomials 14(x2-1)(x2+1) and 18(x4-1)(x+1) is

Question

The LCM of polynomials 14(x2-1)(x2+1) and 18(x4-1)(x+1) is (A) 126(x+1)(x2+1)(x-1) (B) 126(x+1)(x2+1)(x2-1) (C) 126(x+1)2(x2+1)(x-1)2 (D) 126(x+1)(x2+1)(x-1)2

Tardigrade Admin · Accepted Answer

Factorize the given polynomials. The product of all the factors with highest exponents is LCM.

Q. The LCM of polynomials $14 (x^{2} - 1) (x^{2} + 1)$ and $18 (x^{4} - 1) (x + 1)$ is

$126 (x + 1) (x^{2} + 1) (x - 1)$

$126 (x + 1) (x^{2} + 1) (x^{2} - 1)$

$126 (x + 1)^{2} (x^{2} + 1) (x - 1)^{2}$

$126 (x + 1) (x^{2} + 1) (x - 1)^{2}$

Factorize the given polynomials. The product of all the factors with highest exponents is LCM.

Q. The LCM of polynomials 14(x2−1)(x2+1) and 18(x4−1)(x+1) is

126(x+1)(x2+1)(x−1)

126(x+1)(x2+1)(x2−1)

126(x+1)2(x2+1)(x−1)2

126(x+1)(x2+1)(x−1)2

Factorize the given polynomials. The product of all the factors with highest exponents is LCM.

Q. The LCM of polynomials $14 (x^{2} - 1) (x^{2} + 1)$ and $18 (x^{4} - 1) (x + 1)$ is

$126 (x + 1) (x^{2} + 1) (x - 1)$

$126 (x + 1) (x^{2} + 1) (x^{2} - 1)$

$126 (x + 1)^{2} (x^{2} + 1) (x - 1)^{2}$

$126 (x + 1) (x^{2} + 1) (x - 1)^{2}$