The kinetic energy of an electron, which is accelerated in the potential difference of 100 volts, is

Question

The kinetic energy of an electron, which is accelerated in the potential difference of 100 volts, is (A) 416.6 cal (B) 6.636 cal (C) 1.602 × 10-17 J  (D) 1.6 × 104 J

Tardigrade Admin · Accepted Answer

Potential difference (V)=100 volts. Kinetic energy of an electron (K.E.) =e V=(1.6 × 10-19) × 100 =1.6 × 10-17 joule

Q. The kinetic energy of an electron, which is accelerated in the potential difference of $100$ volts, is

416.6 cal

6.636 cal

$1.602 \times 1 0^{- 17} J$

$1.6 \times 1 0^{4} J$

Potential difference $(V) = 100$ volts.
Kinetic energy of an electron (K.E.)
$= e V = (1.6 \times 1 0^{- 19}) \times 100$
$= 1.6 \times 1 0^{- 17}$ joule

Q. The kinetic energy of an electron, which is accelerated in the potential difference of 100 volts, is

416.6 cal

6.636 cal

1.602×10−17J

1.6×104J

Potential difference (V)=100 volts. Kinetic energy of an electron (K.E.) =eV=(1.6×10−19)×100 =1.6×10−17 joule

Q. The kinetic energy of an electron, which is accelerated in the potential difference of $100$ volts, is

$1.602 \times 1 0^{- 17} J$

$1.6 \times 1 0^{4} J$

Potential difference $(V) = 100$ volts.
Kinetic energy of an electron (K.E.)
$= e V = (1.6 \times 1 0^{- 19}) \times 100$
$= 1.6 \times 1 0^{- 17}$ joule