The kinetic energy of an electron revolving around a nucleus will be

Question

The kinetic energy of an electron revolving around a nucleus will be (A) four times of its P.E. (B) twice of its P. E. (C) equal to its P. E. (D) half of its P. E.

Tardigrade Admin · Accepted Answer

K.E. of electron =(13.6 Z 2/n2) eV P.E. of electron =(2 × 13.6 Z 2/n2) eV ∴ K.E. of electron =(1/2) × P.E. of electron

Q. The kinetic energy of an electron revolving around a nucleus will be

four times of its P.E.

twice of its P. E.

equal to its P. E.

half of its P. E.

K.E. of electron $= \frac{13.6 Z ^{2}}{n ^{2}} e V$
P.E. of electron $= \frac{2 \times 13.6 Z ^{2}}{n ^{2}} e V$
$∴$ K.E. of electron $= \frac{1}{2} \times$ P.E. of electron

Q. The kinetic energy of an electron revolving around a nucleus will be

four times of its P.E.

twice of its P. E.

equal to its P. E.

half of its P. E.

K.E. of electron =n213.6Z2​eV P.E. of electron =n22×13.6Z2​eV ∴ K.E. of electron =21​× P.E. of electron

K.E. of electron $= \frac{13.6 Z ^{2}}{n ^{2}} e V$
P.E. of electron $= \frac{2 \times 13.6 Z ^{2}}{n ^{2}} e V$
$∴$ K.E. of electron $= \frac{1}{2} \times$ P.E. of electron