The K α X -ray emission line of tungsten occurs at λ = 0 text. 0 2 1 textnm text. The energy difference between K and L levels in this atom is about

Question

The K α X -ray emission line of tungsten occurs at λ = 0 text. 0 2 1 textnm text. The energy difference between K and L levels in this atom is about (A) 0 . 5 1 text MeV (B) 1. 2 text MeV (C) 5 9 text keV (D) 1 3 text. 6 text eV

Tardigrade Admin · Accepted Answer

λ k α =0 text.021 textnm=0 text.21 overset° textA Since, λ k α corresponds to the transition of an electron from L-shell to K-shell, therefore E L â¡-Eâ¡K â¡=( textin eV)=(1 2 3 7 5/λ (in overset° A))=(1 2 3 7 5/0 text.21)≈ 58928 texteV or Δ E = 59 textkeV

Q. The $K_{α}$ $X$ -ray emission line of tungsten occurs at $λ = 0.021 nm .$ The energy difference between $K$ and $L$ levels in this atom is about

$0.51 MeV$

$1.2 MeV$

$59 keV$

$13.6 eV$

$λ_{k α} = 0.021 nm = 0.21 A^{\circ}$
Since, $λ_{k α}$ corresponds to the transition of an electron from L-shell to K-shell, therefore
$E_{L} - E_{K} = (in eV) = \frac{12375}{λ ( in A ^{\circ} )} = \frac{12375}{0 .21} \approx 58928 eV$
or $Δ E = 59 keV$

Q. The Kα​ X -ray emission line of tungsten occurs at λ=0.021nm. The energy difference between K and L levels in this atom is about

0.51 MeV

1.2 MeV

59 keV

13.6 eV