The ionization constant of a weak electrolyte is 25× 10-6 while the equivalent conductance of its 0.01 M solution is 19.6 text S text cm2eq-1 . The equivalent conductance of the electrolyte at infinite dilution (in S text cm2eq-1 ) will be

Question

The ionization constant of a weak electrolyte is 25× 10-6 while the equivalent conductance of its 0.01 M solution is 19.6 text S text cm2eq-1 . The equivalent conductance of the electrolyte at infinite dilution (in S text cm2eq-1 ) will be (A) 340 (B) 208 (C) 364 (D) 392

Tardigrade Admin · Accepted Answer

Sol. underset beginsmallmatrix C C(1-α ) endsmallmatrix mathopHA underset beginsmallmatrix 0 Cα endsmallmatrix mathopH+ + underset beginsmallmatrix 0 Cα endsmallmatrix mathopA- K=(C.α .Cα /C(1-α ))=(Cα 2/1-α )≃ Cα 2 25× 10-6=10-2× α 2 α =5× 10-2 α =( Lambda c/ Lambda ∞ ) Lambda ∞ =( Lambda c/α )=(19.6/5× 102)=382S cm2eq-1

Q. The ionization constant of a weak electrolyte is 25×10−6 while the equivalent conductance of its 0.01 M solution is 19.6Scm2eq−1 . The equivalent conductance of the electrolyte at infinite dilution (in Scm2eq−1 ) will be

340

208

364

392

Sol. CC(1−α)​HA​0Cα​H+​+0Cα​A−​ K=C(1−α)C.α.Cα​=1−αCα2​≃Cα2 25×10−6=10−2×α2 α=5×10−2 α=Λ∞Λc​ Λ∞=αΛc​=5×10219.6​=382Scm2eq−1

Q. The ionization constant of a weak electrolyte is $25 \times 10^{- 6}$ while the equivalent conductance of its 0.01 M solution is $19.6 S c m^{2} e q^{- 1}$ . The equivalent conductance of the electrolyte at infinite dilution (in $S c m^{2} e q^{- 1}$ ) will be