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Tardigrade
Question
Chemistry
The ionisation potential of K would be numerically equal to
Q. The ionisation potential of K would be numerically equal to
2148
189
Solutions
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A
Electron affinity
13%
B
Electronegativity of K
18%
C
Electron affinity of
K
+
59%
D
Ionization energy of Ca
11%
Solution:
K
(
g
)
+
I
E
⟶
K
+
(
g
)
+
e
−
K
+
(
g
)
+
e
−
→
K
(
g
)
+
E
A
Second equation is reverse of the first. The energy released in the second process would be equal to the energy absorbed in the first.